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I was just curious if anyone knew how to calculate/figure out the time keeping used by the Imperium. Such as how to come up with the year?
Any help is apreciated!
Dark Eldar: 13-wins/ 0-draws / 3-loss
Imperial Fists SM: 4/1/4 1500 Annan 190th IG: 9/1/2 - retired
Chaos Daemons: 3/0/2 (stupid Null-zone)
I'm sure there was another thread on this recently, but I can't find it...
Today's date would be 0032006.M3.
The first digit is the "check number". It's a way of verifying a particular date. The lower the number, the more likely it is to be accurate. 0 refers to an event with the Sol system, 1 to a message send with a direct psychic link to Terra, 2-8 through various forms of "source corroberation", presumably using psychic connnections which expand out form earth, right up to 9, which is only ever gives an approximate date.
The next 3 digits are the year fraction number. To get a normal calendar date into that, simply divide the current "year day" (days into the year, regardless of weeks or months) by 1000.
The next 3 are the year number within the current millenium, going up to 999. Then it switches to the "M" notation, which is an indication of the millenium in which the specified event took place. It follows the "rule of the centuries" here, That is to say, the 40K date follows the "Xth millenium" numbers even when it's written in this form. For our dating system, the first year of the 41st millenium would be 40001, but in the 40K date, 41 is used to set the millennium.
Hope that helps. A better explanation can be found in the back of the 3rd edition 40K rulebok.
So the date today is 0014007.M3, yeah?
Might be the wrong information I provided him. I thought it was divide by 1000. Sorry 'bout that.
Actually you both said divide by 1000. =)
So, for the 2nd, 3rd and 4th letters you do:
[Number of days into year] / [Number of days in the year]
So 15/365.25, yeah?