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Hello everyone. I was wondering if someone could post the correct math for the percent chance to hit with twin-linked BS2. Apparently TLBS2 is better than BS3 but not quite BS4, but I have done a bit of searching and was unable to find a conclusion. Sorry if this has been asked before. Thanks in advance =)
Alright, I'm assuming this is for tau gun drones (as i think they have the only TL bs2 weapon.)
So....... The chance to hit regularly with a Bs 2 is 33.33%. So 66.66% of the time it misses. So take 33.33%(the second rolling of the dice if you miss, the % to see if you hit) of 66.66(the chance you miss), which comes to 22.21778%. So add that to 33.33% and you get 55.551%. Which is a little better than BS3(50%) and a little worse than Bs4(66.6%).
I belive this is right, if not someone please correct me.
Last edited by ZombieKiller; April 21st, 2006 at 01:46.
Ah, there we go. Thank you much!
Now, I'm not a math wiz or anything, so feel free to school me on that aspect...
When you roll the first die you have 33.33% of getting a hit. If that doesn't happen you roll again. You are rolling the same die trying for the same result. I don't see how the probability would change.
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Because you get two attempts at a hit. If you succeed the first attempt, you don't get to try again. But if you fail, you get a do-over. That raises the probability a bit.Originally Posted by Lord Commander Thule
In simpler terms, what has a better chance at rolling a 5 or a 6 on a die? A single roll, or a single roll that you can roll again if you miss it?
simply check the forum. we spend 3 pages crunching this out for you guys....here ya go:
http://www.librarium-online.com/foru...ht=probability (Mathhammer40K: calculating to-hit probability with rerolls)
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