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Im pretty new to warhammer and I've read the rule book and looked at the charts but one thing just doesnt make sense to me.
Say im shooting at a target and I have 3 BS. The target is in the woods long range and lone character. With 3 BS it would be a 4+ to hit but then a -3 modifier. Part of me thinks the -1 modifier applies to BS or there would be no advantage in having 7 8 or 9 ballistic skills since they would all be 2+ and reduced -3 to hit, but it also doesnt make sense to reduce a Ballistic skill to 0 or -1 or -2. I know its in the rule book im just having a hard time figuring it out especially since coming from 40k. I see the rules for 7+ to hit but im confused howu determine that especially because i thought 6's were a naturla hit. Any clariication would be great.
with BS 3 and a -3 mod you would be hitting on 7+.
the same situation works in reverse with large targets getting a +1 to hit
in all respects shooting modifiers will subtract from the ballistic skill indefinently, might not make a lot of sence but try thinking of it as not so much the ballistic skill dropping but the chances of hitting the target dropping.
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Hmm, well...if you need 7+ to hit, look at the table and follow what that says. You've got to roll the 6 then the number in that table. 6's are only a natural hit in close combat, not shooting - that should clear up any problems.
The benefit of a huge BS will only come in useful when facing an opponent that can rack up a hefty modifier - a charging unit of (flying) skirmishers will be nearly impossible to hit for most, but with BS8+ it will still be easy.
Having an army and not owning a rulebook is like owning a car with no steering wheel.Originally Posted by amishcellphone
Try not to look at it as modifying ballistic skill but modifying what you need to hit. For example a BS of 3 means you hit on a 4+, you then modify the 4+ for things like long range and cover etc. Hence having a BS of 6 means your starting point for modifiers is a 1, making it much easier to hit with than a grunt with BS3.
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