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So my buddy and I were discussing the mechanics of the nodal grid when more than 3 monoliths were involved, and took two different takes. The way he sees it, so long as there is 24" around the perimeter you get a nodal grid, where as I see it you have to have no more than the 24" between each. The following should illustrate nicely:
his:
24"
+----------+
| |
| | 24" = 24 sq inch nodal grid (~24" diagonal)
| |
+----------+
mine:
~17"
+-------+
| / |
| / | ~17" =~17 sq inch nodal grid (24" diagonal)
| / 24"|
+-------+
I'd be more than happy with the first version, but I really do think that the second one is the correct one.
What do y'all think?
-------------------
Edit: Right, I'm an idot... HTML doesn't do white space, pretend the above are squares
When seeking the ultimate question remember 6*9==42 only in base 13.
For each Triangle of 3 Liths a grid is formed, so just make as many as you can given the positioning of the Liths at the time.
Ok, yeah. I should have seen that. I got too hung up on optimizing the area for a particular shape that I didn't think of it that way.
And to correct my math from above that should be 576" square and 288" square, repectively. Need to not be lazy with the math.....
For those who are currious, the two triangles that you could form would give you a max area of ~498" square.
When seeking the ultimate question remember 6*9==42 only in base 13.
As long as each 'lith is within 24" of the two 'Liths its connecting to you have a grid. If anywhere one or more of the 'liths is more than 24" away from one of its connecting 'liths the grid is broken down except where 3 or more 'liths are still within 24" of each other.
Not every 'lith needs to be within 24" of each other 'lith, but each 'lith has to be within 24" of at least 2 others for the grid to form. Your ideal shape with 5 'liths would probably be as follows:
A----B----C
-\---------/
--\D----E/
With the Broad end facing the opponent to provide maximum nightshield coverage.
A is within 24" of B and D
B is within 24" of A and C
C is within 24" of B and E
D is within 24" of A and E
E is within 24" of D and C
Last edited by Sabe; March 26th, 2008 at 01:51.
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